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Logseq/assets/2장_선형방정식_Ax_=_b_풀기_1784805780272_0.edn
songyc macbook 20f7d6a3e1 docs: 2장 2차 하이라이트 11개 연결 (소거 예제, E 식10, A=LU 증명, K4·T4·역행렬) 
- area 하이라이트 이미지 11개 추출 (p.76 식2~5, p.91 식10, p.100 식3~4, p.122 식8, p.125 식10~12)
- 2.1/2.2/2.3/2.5 페이지의 해당 위치에 링크+이미지 참조 삽입

Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01G8rNxLqi5rYjRamC8uwiJW
2026-07-24 22:19:15 +09:00

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:content {:text "Ar= b 는 ( 행렬 A 의 각 행으로부터 얻는) 개의 방정식 으로 이루어진다."},
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:content {:text "행렬 A 와 U 는 최대 랭크 (full rank ) 를 갖는다 ."},
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:content {:text "이 문제를 해결하는 방법 은 간단 하다. 0 을 포함한 2행 과 5를 포함한 3 행 을 교환 "},
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:content {:text "열이 선형 종속인경우 , 피벗 위치에 0 이 반드시 생긴다 . "},
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:content {:text "특이행렬 (singular "},
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:content {:text "벡터 b를 행렬 A의 추가 열로 포함하는 것이다. 이와 같은 행렬 [A 이를첨가 행렬(augmented matrix)이라 한다."},
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:content {:text "치환 행렬 P "},
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:content {:text "모든 소거법 단계는 행렬 곱으로 수행 할 수 있다 ."},
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:content {:text "기본 소거 단계는 방정식 에서 방정식 에 ℓ를 곱한 것을 빼는 것이다 "},
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:content {:text "E의 역행렬 은 행 에 ( j행) xl」 를 더하는 것"},
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:content {:text "렬 E의 역행렬 을 특별히 L이라 한다"},
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:content {:text "\"X\" 정사각 행렬 A의 역행렬이 존재하려면 \" 개의 선형독립인 열이 있어야 한다. "},
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:content {:text "가역행렬"},
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:content {:text "모든 행렬이 역행렬을 갖는 것은 아니다."},
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:content {:text "행렬이 가역 행렬 이려면 이 행렬 의 열들이 선형독립 이어야 한다 ."},
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:content {:text "A 의 역행렬 이 존재 하는 경우, Az = b의 유일한 해는 = A- b이다 . "},
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:content {:text "정사각행렬이 가역 행렬일 필요 충분조건 은 이 행렬의 열들이 선형독립 인 것이다"},
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:content {:text "Ar=0 이 되는 영벡터가 아닌 벡터 가 존재 한다고 가정하자 . 그러면 행렬 A는 선형 종속인 열 을 갖는다. 따라서 행렬 A의 역행렬 은 존재 하지 않는다 "},
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:content {:text "수 ad-bc는 2x2 행렬 의 행렬식"},
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:content {:text "상삼각 행렬은 주 대각성분 d가 0 이 아닌 경우 역행렬을 갖는다"},
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:content {:text "2×2 행렬이 가역행렬일 필요충분조건은 ad -bc 가 0 이 아닌 것"},
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:content {:text "가우스 - 조르단 소거법( Gauss -Jordan elimination "},
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:content {:text "소거법의 비용"},
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:content {:text "L에서 가 제자리 에 있는 이유 를 설명하는 방법을 "},
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:content {:text "행 교환 이 없고 피벗에 0이 없는 A= LU 분해 는 언제 가능한가"},
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:content {:text "쪽 상단 모서리에 있는 모든 kXk 부분행렬이 가역 행렬일 때만 가능하다"},
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:content {:text "치환 행렬 은 모든 행 에 하나 의 1만 있고 , 모든 열에도 하나 의 1만 있다. 그 외의 모든 성분은 0"},
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:content {:text "홀수 치환 행렬"},
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:content {:text "짝수 치환행렬"},
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:content {:text "각 피벗을 피벗 아래에 있는 모든 수 보다 크게 만들 때, 행렬 L 의 모든 성분들은 1 이하 가 된다 "},
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:content {:text "'부분 피벳"},
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:content {:text "전치 행렬"},
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:content {:text "대칭행렬을 S 로 표기"},
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:content {:text "대칭 행렬의 역행렬 은 대칭 행렬 이다"},
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